Seitarounakaosm

 x = 1 y = 2 Ok So prefer the elimination method, but you can do this with substitution as well First put the equations on top of each other x 2y= 5 2x3y=4 Then find the variable that would be easiest to cancel out I think it's x because you only have to modify one of the equations Let's multiply the first equation by 2 This will allow us to cancel out the two x's in theSolve the following system by using the GaussJordan elimination method xy z = 5 2x3y 5z = 8 4x5z = 2 Solution The augmented matrix of the system is the following 1 1 1 5 2 3 5 8 4 0 5 2 We will now perform row operations until we obtain a matrix in reduced row echelon form 1 1 1 5 2 3 5 8 4 0 5 2 −−−−−→R 2−2R 1 1 1 1 5 0Divide both sides by 5 2x y = 750 (2) Step 3 Solve (1) and (2) using elimination method x y = 548 (1) 2x y = 750 (2) In the above two equations, y is having the same coefficient, that is 1 Multiply the first equation by 1 to get the coefficient of 1 And keep the second equation as it is Then,...